2d+4(d-3)=3

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Solution for 2d+4(d-3)=3 equation: 



2d+4(d-3)=3

We move all terms to the left:

2d+4(d-3)-(3)=0

We multiply parentheses

2d+4d-12-3=0

We add all the numbers together, and all the variables

6d-15=0

We move all terms containing d to the left, all other terms to the right

6d=15

d=15/6

d=2+1/2

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