2d+4-2=4(d+1)-2d

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Solution for 2d+4-2=4(d+1)-2d equation: 



2d+4-2=4(d+1)-2d

We move all terms to the left:

2d+4-2-(4(d+1)-2d)=0

We add all the numbers together, and all the variables

2d-(4(d+1)-2d)+2=0



We calculate terms in parentheses: -(4(d+1)-2d), so:

4(d+1)-2d

We add all the numbers together, and all the variables

-2d+4(d+1)

We multiply parentheses

-2d+4d+4

We add all the numbers together, and all the variables

2d+4

Back to the equation:

-(2d+4)



We get rid of parentheses

2d-2d-4+2=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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