2d-(d-4)=d-4(d+4)

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Solution for 2d-(d-4)=d-4(d+4) equation: 



2d-(d-4)=d-4(d+4)

We move all terms to the left:

2d-(d-4)-(d-4(d+4))=0

We get rid of parentheses

2d-d-(d-4(d+4))+4=0



We calculate terms in parentheses: -(d-4(d+4)), so:

d-4(d+4)

We multiply parentheses

d-4d-16

We add all the numbers together, and all the variables

-3d-16

Back to the equation:

-(-3d-16)



We add all the numbers together, and all the variables

d-(-3d-16)+4=0

We get rid of parentheses

d+3d+16+4=0

We add all the numbers together, and all the variables

4d+20=0

We move all terms containing d to the left, all other terms to the right

4d=-20

d=-20/4

d=-5

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