2d-3(4-d)=2-5(d-3)

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Solution for 2d-3(4-d)=2-5(d-3) equation: 



2d-3(4-d)=2-5(d-3)

We move all terms to the left:

2d-3(4-d)-(2-5(d-3))=0

We add all the numbers together, and all the variables

2d-3(-1d+4)-(2-5(d-3))=0

We multiply parentheses

2d+3d-(2-5(d-3))-12=0



We calculate terms in parentheses: -(2-5(d-3)), so:

2-5(d-3)

determiningTheFunctionDomain
-5(d-3)+2

We multiply parentheses

-5d+15+2

We add all the numbers together, and all the variables

-5d+17

Back to the equation:

-(-5d+17)



We add all the numbers together, and all the variables

5d-(-5d+17)-12=0

We get rid of parentheses

5d+5d-17-12=0

We add all the numbers together, and all the variables

10d-29=0

We move all terms containing d to the left, all other terms to the right

10d=29

d=29/10

d=2+9/10

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