2d-3(d-4)=2(d+6)

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Solution for 2d-3(d-4)=2(d+6) equation:


Simplifying
2d + -3(d + -4) = 2(d + 6)

Reorder the terms:
2d + -3(-4 + d) = 2(d + 6)
2d + (-4 * -3 + d * -3) = 2(d + 6)
2d + (12 + -3d) = 2(d + 6)

Reorder the terms:
12 + 2d + -3d = 2(d + 6)

Combine like terms: 2d + -3d = -1d
12 + -1d = 2(d + 6)

Reorder the terms:
12 + -1d = 2(6 + d)
12 + -1d = (6 * 2 + d * 2)
12 + -1d = (12 + 2d)

Add '-12' to each side of the equation.
12 + -12 + -1d = 12 + -12 + 2d

Combine like terms: 12 + -12 = 0
0 + -1d = 12 + -12 + 2d
-1d = 12 + -12 + 2d

Combine like terms: 12 + -12 = 0
-1d = 0 + 2d
-1d = 2d

Solving
-1d = 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-1d + -2d = 2d + -2d

Combine like terms: -1d + -2d = -3d
-3d = 2d + -2d

Combine like terms: 2d + -2d = 0
-3d = 0

Divide each side by '-3'.
d = 0

Simplifying
d = 0

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