2d2-19d+14=-6d

Solution for 2d2-19d+14=-6d equation:

2d^2-19d+14=-6d

We move all terms to the left:

2d^2-19d+14-(-6d)=0

We get rid of parentheses

2d^2-19d+6d+14=0

We add all the numbers together, and all the variables

2d^2-13d+14=0

a = 2; b = -13; c = +14;
Δ = b2-4ac
Δ = -132-4·2·14
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{57}}{2*2}=\frac{13-\sqrt{57}}{4}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{57}}{2*2}=\frac{13+\sqrt{57}}{4}
$