2d=3d-(d/0.45)

Solution for 2d=3d-(d/0.45) equation:

2d=3d-(d/0.45)

We move all terms to the left:

2d-(3d-(d/0.45))=0

We add all the numbers together, and all the variables

2d-(3d-(+d/0.45))=0

We multiply all the terms by the denominator


2d*0.45))-(3d-(+d=0

We add all the numbers together, and all the variables

d+2d*0.45))-(3d-(=0

Wy multiply elements

0d^2+d=0

We add all the numbers together, and all the variables

d^2+d=0

a = 1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*1}=\frac{-2}{2}
=-1
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*1}=\frac{0}{2}
=0
$