2e-9+8e=3(2e-4)+3

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Solution for 2e-9+8e=3(2e-4)+3 equation: 



2e-9+8e=3(2e-4)+3

We move all terms to the left:

2e-9+8e-(3(2e-4)+3)=0

We add all the numbers together, and all the variables

10e-(3(2e-4)+3)-9=0



We calculate terms in parentheses: -(3(2e-4)+3), so:

3(2e-4)+3

We multiply parentheses

6e-12+3

We add all the numbers together, and all the variables

6e-9

Back to the equation:

-(6e-9)



We get rid of parentheses

10e-6e+9-9=0

We add all the numbers together, and all the variables

4e=0

e=0/4

e=0

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