2f(f)+27f-29=0

Solution for 2f(f)+27f-29=0 equation:

Simplifying
2f(f) + 27f + -29 = 0

Multiply f * f
2f2 + 27f + -29 = 0

Reorder the terms:
-29 + 27f + 2f2 = 0

Solving
-29 + 27f + 2f2 = 0

Solving for variable 'f'.

Factor a trinomial.
(-29 + -2f)(1 + -1f) = 0

Subproblem 1
Set the factor '(-29 + -2f)' equal to zero and attempt to solve:

Simplifying
-29 + -2f = 0

Solving
-29 + -2f = 0

Move all terms containing f to the left, all other terms to the right.

Add '29' to each side of the equation.
-29 + 29 + -2f = 0 + 29

Combine like terms: -29 + 29 = 0
0 + -2f = 0 + 29
-2f = 0 + 29

Combine like terms: 0 + 29 = 29
-2f = 29

Divide each side by '-2'.
f = -14.5

Simplifying
f = -14.5
Subproblem 2
Set the factor '(1 + -1f)' equal to zero and attempt to solve:

Simplifying
1 + -1f = 0

Solving
1 + -1f = 0

Move all terms containing f to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1f = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1f = 0 + -1
-1f = 0 + -1

Combine like terms: 0 + -1 = -1
-1f = -1

Divide each side by '-1'.
f = 1

Simplifying
f = 1
Solution
f = {-14.5, 1}