2f+3(f+1)=4(f+2)-(f+3)

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Solution for 2f+3(f+1)=4(f+2)-(f+3) equation: 



2f+3(f+1)=4(f+2)-(f+3)

We move all terms to the left:

2f+3(f+1)-(4(f+2)-(f+3))=0

We multiply parentheses

2f+3f-(4(f+2)-(f+3))+3=0



We calculate terms in parentheses: -(4(f+2)-(f+3)), so:

4(f+2)-(f+3)

We multiply parentheses

4f-(f+3)+8

We get rid of parentheses

4f-f-3+8

We add all the numbers together, and all the variables

3f+5

Back to the equation:

-(3f+5)



We add all the numbers together, and all the variables

5f-(3f+5)+3=0

We get rid of parentheses

5f-3f-5+3=0

We add all the numbers together, and all the variables

2f-2=0

We move all terms containing f to the left, all other terms to the right

2f=2

f=2/2

f=1

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