2f+3(f-7)=19

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Solution for 2f+3(f-7)=19 equation: 



2f+3(f-7)=19

We move all terms to the left:

2f+3(f-7)-(19)=0

We multiply parentheses

2f+3f-21-19=0

We add all the numbers together, and all the variables

5f-40=0

We move all terms containing f to the left, all other terms to the right

5f=40

f=40/5

f=8

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