2f+3-5f=6+2(4-f)

Solution for 2f+3-5f=6+2(4-f) equation:

2f+3-5f=6+2(4-f)

We move all terms to the left:

2f+3-5f-(6+2(4-f))=0

We add all the numbers together, and all the variables

2f-5f-(6+2(-1f+4))+3=0

We add all the numbers together, and all the variables

-3f-(6+2(-1f+4))+3=0


We calculate terms in parentheses: -(6+2(-1f+4)), so:

6+2(-1f+4)

determiningTheFunctionDomain
2(-1f+4)+6

We multiply parentheses

-2f+8+6

We add all the numbers together, and all the variables

-2f+14

Back to the equation:

-(-2f+14)


We get rid of parentheses

-3f+2f-14+3=0

We add all the numbers together, and all the variables

-1f-11=0

We move all terms containing f to the left, all other terms to the right

-f=11

f=11/-1

f=-11