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2f^2-15f-27=0
a = 2; b = -15; c = -27;
Δ = b2-4ac
Δ = -152-4·2·(-27)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-21}{2*2}=\frac{-6}{4} =-1+1/2 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+21}{2*2}=\frac{36}{4} =9 $
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