2g+(-6+3g)=1-g

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Solution for 2g+(-6+3g)=1-g equation: 



2g+(-6+3g)=1-g

We move all terms to the left:

2g+(-6+3g)-(1-g)=0

We add all the numbers together, and all the variables

2g+(3g-6)-(-1g+1)=0

We get rid of parentheses

2g+3g+1g-6-1=0

We add all the numbers together, and all the variables

6g-7=0

We move all terms containing g to the left, all other terms to the right

6g=7

g=7/6

g=1+1/6

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