2g+1+g=3(g-2)+7

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Solution for 2g+1+g=3(g-2)+7 equation: 



2g+1+g=3(g-2)+7

We move all terms to the left:

2g+1+g-(3(g-2)+7)=0

We add all the numbers together, and all the variables

3g-(3(g-2)+7)+1=0



We calculate terms in parentheses: -(3(g-2)+7), so:

3(g-2)+7

We multiply parentheses

3g-6+7

We add all the numbers together, and all the variables

3g+1

Back to the equation:

-(3g+1)



We get rid of parentheses

3g-3g-1+1=0

We add all the numbers together, and all the variables

=0

g=0/1

g=0

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