2g+29(-3+4g)=1-g

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Solution for 2g+29(-3+4g)=1-g equation: 



2g+29(-3+4g)=1-g

We move all terms to the left:

2g+29(-3+4g)-(1-g)=0

We add all the numbers together, and all the variables

2g+29(4g-3)-(-1g+1)=0

We multiply parentheses

2g+116g-(-1g+1)-87=0

We get rid of parentheses

2g+116g+1g-1-87=0

We add all the numbers together, and all the variables

119g-88=0

We move all terms containing g to the left, all other terms to the right

119g=88

g=88/119

g=88/119

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