2g+3(g-4)=2(2g-6)+g

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Solution for 2g+3(g-4)=2(2g-6)+g equation: 



2g+3(g-4)=2(2g-6)+g

We move all terms to the left:

2g+3(g-4)-(2(2g-6)+g)=0

We multiply parentheses

2g+3g-(2(2g-6)+g)-12=0



We calculate terms in parentheses: -(2(2g-6)+g), so:

2(2g-6)+g

We add all the numbers together, and all the variables

g+2(2g-6)

We multiply parentheses

g+4g-12

We add all the numbers together, and all the variables

5g-12

Back to the equation:

-(5g-12)



We add all the numbers together, and all the variables

5g-(5g-12)-12=0

We get rid of parentheses

5g-5g+12-12=0

We add all the numbers together, and all the variables

=0

g=0/1

g=0

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