2g+4/6=(g+2)/3

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Solution for 2g+4/6=(g+2)/3 equation: 



2g+4/6=(g+2)/3

We move all terms to the left:

2g+4/6-((g+2)/3)=0

We calculate fractions


2g+(-((g+2)*6)/()+()/()=0



We calculate terms in parentheses: +(-((g+2)*6)/()+()/(), so:

-((g+2)*6)/()+()/(

We add all the numbers together, and all the variables

-((g+2)*6)/()+1

We multiply all the terms by the denominator


-((g+2)*6)+1*()



We calculate terms in parentheses: -((g+2)*6), so:

(g+2)*6

We multiply parentheses

6g+12

Back to the equation:

-(6g+12)



We add all the numbers together, and all the variables

-(6g+12)

We get rid of parentheses

-6g-12

Back to the equation:

+(-6g-12)



We get rid of parentheses

2g-6g-12=0

We add all the numbers together, and all the variables

-4g-12=0

We move all terms containing g to the left, all other terms to the right

-4g=12

g=12/-4

g=-3

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