2g+6=3(g-2)

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Solution for 2g+6=3(g-2) equation: 



2g+6=3(g-2)

We move all terms to the left:

2g+6-(3(g-2))=0



We calculate terms in parentheses: -(3(g-2)), so:

3(g-2)

We multiply parentheses

3g-6

Back to the equation:

-(3g-6)



We get rid of parentheses

2g-3g+6+6=0

We add all the numbers together, and all the variables

-1g+12=0

We move all terms containing g to the left, all other terms to the right

-g=-12

g=-12/-1

g=+12

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