2g-1=3-(4-2(5-2g)-g)

Solution for 2g-1=3-(4-2(5-2g)-g) equation:

2g-1=3-(4-2(5-2g)-g)

We move all terms to the left:

2g-1-(3-(4-2(5-2g)-g))=0

We add all the numbers together, and all the variables

2g-(3-(4-2(-2g+5)-g))-1=0


We calculate terms in parentheses: -(3-(4-2(-2g+5)-g)), so:

3-(4-2(-2g+5)-g)

determiningTheFunctionDomain
-(4-2(-2g+5)-g)+3


We calculate terms in parentheses: -(4-2(-2g+5)-g), so:

4-2(-2g+5)-g

determiningTheFunctionDomain
-2(-2g+5)-g+4

We add all the numbers together, and all the variables

-1g-2(-2g+5)+4

We multiply parentheses

-1g+4g-10+4

We add all the numbers together, and all the variables

3g-6

Back to the equation:

-(3g-6)


We get rid of parentheses

-3g+6+3

We add all the numbers together, and all the variables

-3g+9

Back to the equation:

-(-3g+9)


We get rid of parentheses

2g+3g-9-1=0

We add all the numbers together, and all the variables

5g-10=0

We move all terms containing g to the left, all other terms to the right

5g=10

g=10/5

g=2