2g-1=3-(4-2(5-2g)-g)

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Solution for 2g-1=3-(4-2(5-2g)-g) equation:



2g-1=3-(4-2(5-2g)-g)
We move all terms to the left:
2g-1-(3-(4-2(5-2g)-g))=0
We add all the numbers together, and all the variables
2g-(3-(4-2(-2g+5)-g))-1=0
We calculate terms in parentheses: -(3-(4-2(-2g+5)-g)), so:
3-(4-2(-2g+5)-g)
determiningTheFunctionDomain -(4-2(-2g+5)-g)+3
We calculate terms in parentheses: -(4-2(-2g+5)-g), so:
4-2(-2g+5)-g
determiningTheFunctionDomain -2(-2g+5)-g+4
We add all the numbers together, and all the variables
-1g-2(-2g+5)+4
We multiply parentheses
-1g+4g-10+4
We add all the numbers together, and all the variables
3g-6
Back to the equation:
-(3g-6)
We get rid of parentheses
-3g+6+3
We add all the numbers together, and all the variables
-3g+9
Back to the equation:
-(-3g+9)
We get rid of parentheses
2g+3g-9-1=0
We add all the numbers together, and all the variables
5g-10=0
We move all terms containing g to the left, all other terms to the right
5g=10
g=10/5
g=2

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