2g-3/5(20-10g)+12=-32

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Solution for 2g-3/5(20-10g)+12=-32 equation: 



2g-3/5(20-10g)+12=-32

We move all terms to the left:

2g-3/5(20-10g)+12-(-32)=0



Domain of the equation: 5(20-10g)!=0

g∈R



We add all the numbers together, and all the variables

2g-3/5(-10g+20)+12-(-32)=0

We add all the numbers together, and all the variables

2g-3/5(-10g+20)+44=0

We multiply all the terms by the denominator


2g*5(-10g+20)+44*5(-10g+20)-3=0

Wy multiply elements

10g^2(-+220g(--3=0

We use the square of the difference formula

10g^2(-220g(+3=0

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