2g-3/5(20-10g)+12=-32

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Solution for 2g-3/5(20-10g)+12=-32 equation:



2g-3/5(20-10g)+12=-32
We move all terms to the left:
2g-3/5(20-10g)+12-(-32)=0
Domain of the equation: 5(20-10g)!=0
g∈R
We add all the numbers together, and all the variables
2g-3/5(-10g+20)+12-(-32)=0
We add all the numbers together, and all the variables
2g-3/5(-10g+20)+44=0
We multiply all the terms by the denominator
2g*5(-10g+20)+44*5(-10g+20)-3=0
Wy multiply elements
10g^2(-+220g(--3=0
We use the square of the difference formula
10g^2(-220g(+3=0

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