2g-3/5(20-3g)=12

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Solution for 2g-3/5(20-3g)=12 equation: 



2g-3/5(20-3g)=12

We move all terms to the left:

2g-3/5(20-3g)-(12)=0



Domain of the equation: 5(20-3g)!=0

g∈R



We add all the numbers together, and all the variables

2g-3/5(-3g+20)-12=0

We multiply all the terms by the denominator


2g*5(-3g+20)-12*5(-3g+20)-3=0

Wy multiply elements

10g^2(--60g(--3=0

We use the square of the difference formula

10g^2(+60g(+3=0

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