2g2+23g+11=0

Solution for 2g2+23g+11=0 equation:

2g^2+23g+11=0

a = 2; b = 23; c = +11;
Δ = b2-4ac
Δ = 232-4·2·11
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-21}{2*2}=\frac{-44}{4}
=-11
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+21}{2*2}=\frac{-2}{4}
=-1/2
$