2h*4h=18

Solution for 2h*4h=18 equation:

2h*4h=18

We move all terms to the left:

2h*4h-(18)=0

Wy multiply elements

8h^2-18=0

a = 8; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·8·(-18)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*8}=\frac{-24}{16}
=-1+1/2
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*8}=\frac{24}{16}
=1+1/2
$