2h+3(h+4)=3+4(h+2)

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Solution for 2h+3(h+4)=3+4(h+2) equation: 



2h+3(h+4)=3+4(h+2)

We move all terms to the left:

2h+3(h+4)-(3+4(h+2))=0

We multiply parentheses

2h+3h-(3+4(h+2))+12=0



We calculate terms in parentheses: -(3+4(h+2)), so:

3+4(h+2)

determiningTheFunctionDomain
4(h+2)+3

We multiply parentheses

4h+8+3

We add all the numbers together, and all the variables

4h+11

Back to the equation:

-(4h+11)



We add all the numbers together, and all the variables

5h-(4h+11)+12=0

We get rid of parentheses

5h-4h-11+12=0

We add all the numbers together, and all the variables

h+1=0

We move all terms containing h to the left, all other terms to the right

h=-1

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