2h+3=h/(x+1)

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Solution for 2h+3=h/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

2*h+3 = h/(x+1) // - h/(x+1)

2*h-(h/(x+1))+3 = 0

(-1*h)/(x+1)+2*h+3 = 0

(-1*h)/(x+1)+(2*h*(x+1))/(x+1)+(3*(x+1))/(x+1) = 0

2*h*(x+1)+3*(x+1)-1*h = 0

2*h*x+h+3*x+3 = 0

(2*h*x+h+3*x+3)/(x+1) = 0

(2*h*x+h+3*x+3)/(x+1) = 0 // * x+1

2*h*x+h+3*x+3 = 0

h+3*x+3 = 0 // - h+3

3*x = -(h+3) // : 3

x = (-(h+3))/3

x = (-(h+3))/3

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