2h+3c+f=20

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Solution for 2h+3c+f=20 equation:


Simplifying
2h + 3c + f = 20

Reorder the terms:
3c + f + 2h = 20

Solving
3c + f + 2h = 20

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1f' to each side of the equation.
3c + f + -1f + 2h = 20 + -1f

Combine like terms: f + -1f = 0
3c + 0 + 2h = 20 + -1f
3c + 2h = 20 + -1f

Add '-2h' to each side of the equation.
3c + 2h + -2h = 20 + -1f + -2h

Combine like terms: 2h + -2h = 0
3c + 0 = 20 + -1f + -2h
3c = 20 + -1f + -2h

Divide each side by '3'.
c = 6.666666667 + -0.3333333333f + -0.6666666667h

Simplifying
c = 6.666666667 + -0.3333333333f + -0.6666666667h

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