2h+7+3h-1=4(h-3)-5

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Solution for 2h+7+3h-1=4(h-3)-5 equation: 



2h+7+3h-1=4(h-3)-5

We move all terms to the left:

2h+7+3h-1-(4(h-3)-5)=0

We add all the numbers together, and all the variables

5h-(4(h-3)-5)+6=0



We calculate terms in parentheses: -(4(h-3)-5), so:

4(h-3)-5

We multiply parentheses

4h-12-5

We add all the numbers together, and all the variables

4h-17

Back to the equation:

-(4h-17)



We get rid of parentheses

5h-4h+17+6=0

We add all the numbers together, and all the variables

h+23=0

We move all terms containing h to the left, all other terms to the right

h=-23

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