2h-3/h

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Solution for 2h-3/h equation:


D( h )

h = 0

h = 0

h = 0

h in (-oo:0) U (0:+oo)

2*h-(3/h) = 0

2*h-3*h^-1 = 0

2*h^1-3*h^-1 = 0

(2*h^2-3*h^0)/(h^1) = 0 // * h^2

h^1*(2*h^2-3*h^0) = 0

h^1

2*h^2-3 = 0

2*h^2-3 = 0

DELTA = 0^2-(-3*2*4)

DELTA = 24

DELTA > 0

h = (24^(1/2)+0)/(2*2) or h = (0-24^(1/2))/(2*2)

h = (1*6^(1/2))/2 or h = (-6^(1/2))/2

h in { (-6^(1/2))/2, (1*6^(1/2))/2}

h in { (-6^(1/2))/2, (1*6^(1/2))/2 }

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