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2h/5-7=12h/5-2h+3
We move all terms to the left:
2h/5-7-(12h/5-2h+3)=0
Domain of the equation: 5-2h+3)!=0We add all the numbers together, and all the variables
We move all terms containing h to the left, all other terms to the right
-2h+3)!=-5
h∈R
2h/5-(-2h+12h/5+3)-7=0
We get rid of parentheses
2h/5+2h-12h/5-3-7=0
We multiply all the terms by the denominator
2h+2h*5-12h-3*5-7*5=0
We add all the numbers together, and all the variables
-10h+2h*5-50=0
Wy multiply elements
-10h+10h-50=0
We add all the numbers together, and all the variables
-50!=0
There is no solution for this equation
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