2h2+5h=-4h2+2h

Solution for 2h2+5h=-4h2+2h equation:

2h^2+5h=-4h^2+2h

We move all terms to the left:

2h^2+5h-(-4h^2+2h)=0

We get rid of parentheses

2h^2+4h^2-2h+5h=0

We add all the numbers together, and all the variables

6h^2+3h=0

a = 6; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·6·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*6}=\frac{-6}{12}
=-1/2
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*6}=\frac{0}{12}
=0
$