2i+2(6i-15)=26

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Solution for 2i+2(6i-15)=26 equation: 



2i+2(6i-15)=26

We move all terms to the left:

2i+2(6i-15)-(26)=0

We multiply parentheses

2i+12i-30-26=0

We add all the numbers together, and all the variables

14i-56=0

We move all terms containing i to the left, all other terms to the right

14i=56

i=56/14

i=4

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