2i+7-5i+8=3(5+6i)-12i

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Solution for 2i+7-5i+8=3(5+6i)-12i equation: 



2i+7-5i+8=3(5+6i)-12i

We move all terms to the left:

2i+7-5i+8-(3(5+6i)-12i)=0

We add all the numbers together, and all the variables

2i-5i-(3(6i+5)-12i)+7+8=0

We add all the numbers together, and all the variables

-3i-(3(6i+5)-12i)+15=0



We calculate terms in parentheses: -(3(6i+5)-12i), so:

3(6i+5)-12i

We add all the numbers together, and all the variables

-12i+3(6i+5)

We multiply parentheses

-12i+18i+15

We add all the numbers together, and all the variables

6i+15

Back to the equation:

-(6i+15)



We get rid of parentheses

-3i-6i-15+15=0

We add all the numbers together, and all the variables

-9i=0

i=0/-9

i=0

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