2i-6=3(i-1)

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Solution for 2i-6=3(i-1) equation: 



2i-6=3(i-1)

We move all terms to the left:

2i-6-(3(i-1))=0



We calculate terms in parentheses: -(3(i-1)), so:

3(i-1)

We multiply parentheses

3i-3

Back to the equation:

-(3i-3)



We get rid of parentheses

2i-3i+3-6=0

We add all the numbers together, and all the variables

-1i-3=0

We move all terms containing i to the left, all other terms to the right

-i=3

i=3/-1

i=-3

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