2j+6(3+11j)-51j=5(j-5)+3

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Solution for 2j+6(3+11j)-51j=5(j-5)+3 equation: 



2j+6(3+11j)-51j=5(j-5)+3

We move all terms to the left:

2j+6(3+11j)-51j-(5(j-5)+3)=0

We add all the numbers together, and all the variables

2j+6(11j+3)-51j-(5(j-5)+3)=0

We add all the numbers together, and all the variables

-49j+6(11j+3)-(5(j-5)+3)=0

We multiply parentheses

-49j+66j-(5(j-5)+3)+18=0



We calculate terms in parentheses: -(5(j-5)+3), so:

5(j-5)+3

We multiply parentheses

5j-25+3

We add all the numbers together, and all the variables

5j-22

Back to the equation:

-(5j-22)



We add all the numbers together, and all the variables

17j-(5j-22)+18=0

We get rid of parentheses

17j-5j+22+18=0

We add all the numbers together, and all the variables

12j+40=0

We move all terms containing j to the left, all other terms to the right

12j=-40

j=-40/12

j=-3+1/3

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