2j+6=3(j+2)-j

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Solution for 2j+6=3(j+2)-j equation: 



2j+6=3(j+2)-j

We move all terms to the left:

2j+6-(3(j+2)-j)=0



We calculate terms in parentheses: -(3(j+2)-j), so:

3(j+2)-j

We add all the numbers together, and all the variables

-1j+3(j+2)

We multiply parentheses

-1j+3j+6

We add all the numbers together, and all the variables

2j+6

Back to the equation:

-(2j+6)



We get rid of parentheses

2j-2j-6+6=0

We add all the numbers together, and all the variables

=0

j=0/1

j=0

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