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2j-(5j+2)=-(3j-1)
We move all terms to the left:
2j-(5j+2)-(-(3j-1))=0
We get rid of parentheses
2j-5j-(-(3j-1))-2=0
We calculate terms in parentheses: -(-(3j-1)), so:We add all the numbers together, and all the variables
-(3j-1)
We get rid of parentheses
-3j+1
Back to the equation:
-(-3j+1)
-3j-(-3j+1)-2=0
We get rid of parentheses
-3j+3j-1-2=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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