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2j^2+4j+2=0
a = 2; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$j=\frac{-b}{2a}=\frac{-4}{4}=-1$
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