2k(k+3)=6k

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Solution for 2k(k+3)=6k equation: 



2k(k+3)=6k

We move all terms to the left:

2k(k+3)-(6k)=0

We add all the numbers together, and all the variables

-6k+2k(k+3)=0

We multiply parentheses

2k^2-6k+6k=0

We add all the numbers together, and all the variables

2k^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{4}=0$

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