2k+24=3(k+6)

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Solution for 2k+24=3(k+6) equation: 



2k+24=3(k+6)

We move all terms to the left:

2k+24-(3(k+6))=0



We calculate terms in parentheses: -(3(k+6)), so:

3(k+6)

We multiply parentheses

3k+18

Back to the equation:

-(3k+18)



We get rid of parentheses

2k-3k-18+24=0

We add all the numbers together, and all the variables

-1k+6=0

We move all terms containing k to the left, all other terms to the right

-k=-6

k=-6/-1

k=+6

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