2k+3(k-4)=2(k-3)

Solution for 2k+3(k-4)=2(k-3) equation:

Simplifying
2k + 3(k + -4) = 2(k + -3)

Reorder the terms:
2k + 3(-4 + k) = 2(k + -3)
2k + (-4 * 3 + k * 3) = 2(k + -3)
2k + (-12 + 3k) = 2(k + -3)

Reorder the terms:
-12 + 2k + 3k = 2(k + -3)

Combine like terms: 2k + 3k = 5k
-12 + 5k = 2(k + -3)

Reorder the terms:
-12 + 5k = 2(-3 + k)
-12 + 5k = (-3 * 2 + k * 2)
-12 + 5k = (-6 + 2k)

Solving
-12 + 5k = -6 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-12 + 5k + -2k = -6 + 2k + -2k

Combine like terms: 5k + -2k = 3k
-12 + 3k = -6 + 2k + -2k

Combine like terms: 2k + -2k = 0
-12 + 3k = -6 + 0
-12 + 3k = -6

Add '12' to each side of the equation.
-12 + 12 + 3k = -6 + 12

Combine like terms: -12 + 12 = 0
0 + 3k = -6 + 12
3k = -6 + 12

Combine like terms: -6 + 12 = 6
3k = 6

Divide each side by '3'.
k = 2

Simplifying
k = 2