2k+4(3k-5)=26-9k

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Solution for 2k+4(3k-5)=26-9k equation: 



2k+4(3k-5)=26-9k

We move all terms to the left:

2k+4(3k-5)-(26-9k)=0

We add all the numbers together, and all the variables

2k+4(3k-5)-(-9k+26)=0

We multiply parentheses

2k+12k-(-9k+26)-20=0

We get rid of parentheses

2k+12k+9k-26-20=0

We add all the numbers together, and all the variables

23k-46=0

We move all terms containing k to the left, all other terms to the right

23k=46

k=46/23

k=2

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