2k+4/8=2

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Solution for 2k+4/8=2 equation: 



2k+4/8=2

We move all terms to the left:

2k+4/8-(2)=0

determiningTheFunctionDomain
2k-2+4/8=0

We multiply all the terms by the denominator


2k*8+4-2*8=0

We add all the numbers together, and all the variables

2k*8-12=0

Wy multiply elements

16k-12=0

We move all terms containing k to the left, all other terms to the right

16k=12

k=12/16

k=3/4

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