2k+41/5=9

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Solution for 2k+41/5=9 equation: 



2k+41/5=9

We move all terms to the left:

2k+41/5-(9)=0

determiningTheFunctionDomain
2k-9+41/5=0

We multiply all the terms by the denominator


2k*5+41-9*5=0

We add all the numbers together, and all the variables

2k*5-4=0

Wy multiply elements

10k-4=0

We move all terms containing k to the left, all other terms to the right

10k=4

k=4/10

k=2/5

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