2k+7(3k-4)=7k+36

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Solution for 2k+7(3k-4)=7k+36 equation: 



2k+7(3k-4)=7k+36

We move all terms to the left:

2k+7(3k-4)-(7k+36)=0

We multiply parentheses

2k+21k-(7k+36)-28=0

We get rid of parentheses

2k+21k-7k-36-28=0

We add all the numbers together, and all the variables

16k-64=0

We move all terms containing k to the left, all other terms to the right

16k=64

k=64/16

k=4

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