2k+8=2(k+4)

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Solution for 2k+8=2(k+4) equation: 



2k+8=2(k+4)

We move all terms to the left:

2k+8-(2(k+4))=0



We calculate terms in parentheses: -(2(k+4)), so:

2(k+4)

We multiply parentheses

2k+8

Back to the equation:

-(2k+8)



We get rid of parentheses

2k-2k-8+8=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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