2k-(k-8)=k+(k-2)

Solution for 2k-(k-8)=k+(k-2) equation:

2k-(k-8)=k+(k-2)

We move all terms to the left:

2k-(k-8)-(k+(k-2))=0

We get rid of parentheses

2k-k-(k+(k-2))+8=0


We calculate terms in parentheses: -(k+(k-2)), so:

k+(k-2)

We get rid of parentheses

k+k-2

We add all the numbers together, and all the variables

2k-2

Back to the equation:

-(2k-2)


We add all the numbers together, and all the variables

k-(2k-2)+8=0

We get rid of parentheses

k-2k+2+8=0

We add all the numbers together, and all the variables

-1k+10=0

We move all terms containing k to the left, all other terms to the right

-k=-10

k=-10/-1

k=+10