2k-2k+3k=3

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Solution for 2k-2k+3k=3 equation: 



2k-2k+3k=3

We move all terms to the left:

2k-2k+3k-(3)=0

We add all the numbers together, and all the variables

3k-3=0

We move all terms containing k to the left, all other terms to the right

3k=3

k=3/3

k=1

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