2k-3(4-k)=3k+4=

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Solution for 2k-3(4-k)=3k+4= equation: 



2k-3(4-k)=3k+4=

We move all terms to the left:

2k-3(4-k)-(3k+4)=0

We add all the numbers together, and all the variables

2k-3(-1k+4)-(3k+4)=0

We multiply parentheses

2k+3k-(3k+4)-12=0

We get rid of parentheses

2k+3k-3k-4-12=0

We add all the numbers together, and all the variables

2k-16=0

We move all terms containing k to the left, all other terms to the right

2k=16

k=16/2

k=8

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