2k-3=3k+2(7k+6)

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Solution for 2k-3=3k+2(7k+6) equation: 



2k-3=3k+2(7k+6)

We move all terms to the left:

2k-3-(3k+2(7k+6))=0



We calculate terms in parentheses: -(3k+2(7k+6)), so:

3k+2(7k+6)

We multiply parentheses

3k+14k+12

We add all the numbers together, and all the variables

17k+12

Back to the equation:

-(17k+12)



We get rid of parentheses

2k-17k-12-3=0

We add all the numbers together, and all the variables

-15k-15=0

We move all terms containing k to the left, all other terms to the right

-15k=15

k=15/-15

k=-1

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